Назад
ГДЗ Алгебра 7 клас Тарасенкова (2024)
Роздiл 3. Одночлени i многочлени
Реклама:
Подайте у вигляді добутку вираз:
1) (а + 3)(b – 2) + (а + 3)(2b – 5) = (a + 3)(b – 2 + 2b – 5) = (a + 3)(3b – 7);
2) (2х – 1)(5 + 7x) – (13x + 2)(2x – 1) = (2x – 1)(5 + 7x – 13x – 2) = (2x – 1)(3 – 5x);
3) (4m – 2n)(7n + 1) + (n – 8m)(–7n – 1) = (7n + 1)(4m – 2n – 8m + n) = (7n + 1)(–4m – n);
4) (у – 1)2 – (у – 1)2(5 – 8y) = (y – 1)2(1 – 5 + 8y) = (y – 1)2(8y – 4) = (y2 – 2y + 1)(8y – 4);
5) (а – b)(7а – b) – (b – а)2 = (a – b)(7a – b) + (a – b)2 = (a – b)(7a – b + a – b) = (a – b)8a;
6) (6z – 5)2(1 – z) – (5 – 6z) = (6z – 5)2(1 – z) + (6z – 5) = (6z – 5)((6z – 5)(1 – z) + 1) = (6z – 5)(6z – 6z2 – 5 + 5z + 1) = (6z – 5)(11z – 6z2 – 4).
1) (а + 3)(b – 2) + (а + 3)(2b – 5) = (a + 3)(b – 2 + 2b – 5) = (a + 3)(3b – 7);
2) (2х – 1)(5 + 7x) – (13x + 2)(2x – 1) = (2x – 1)(5 + 7x – 13x – 2) = (2x – 1)(3 – 5x);
3) (4m – 2n)(7n + 1) + (n – 8m)(–7n – 1) = (7n + 1)(4m – 2n – 8m + n) = (7n + 1)(–4m – n);
4) (у – 1)2 – (у – 1)2(5 – 8y) = (y – 1)2(1 – 5 + 8y) = (y – 1)2(8y – 4) = (y2 – 2y + 1)(8y – 4);
5) (а – b)(7а – b) – (b – а)2 = (a – b)(7a – b) + (a – b)2 = (a – b)(7a – b + a – b) = (a – b)8a;
6) (6z – 5)2(1 – z) – (5 – 6z) = (6z – 5)2(1 – z) + (6z – 5) = (6z – 5)((6z – 5)(1 – z) + 1) = (6z – 5)(6z – 6z2 – 5 + 5z + 1) = (6z – 5)(11z – 6z2 – 4).