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ГДЗ Алгебра 8 клас Мерзляк (2025)
§ 1. Раціональні вирази
.jpg?1756641105 "ГДЗ Алгебра 8 клас Мерзляк (2025)")
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7) 1/y – (y+8)/(16- y^2 ) – 2/(y-4) = 1^(\y^2-16)/y + (y+ 8^(\y))/(y^2- 16) – 2^(\y(y+4))/(y-4) – (y^2- 16+y(y+8)- 2y(y+4))/(y(y-4)(y+4)) = (y^2- 16+ y^2+ 8y-2y^2- 8y)/(y(y-4)(y+4)) = (-16)/(y(y^2- 16)) = 16/(y(16- y^2)) = 16/(16y- y^3 );
8) (2b-1)/(4b+2) + 4b/(4b^2- 1) + (2b+1)/(3-6b) = (2b- 1^(\3(2b-1)))/(2(2b+1)) + (4b^(\6))/((2b-1)(2b+1)) – (2b+ 1^(\2(2b+1)))/(3(2b-1)) = (3(2b-1)^2+ 24b-2(2b+1)^2)/(6(2b-1)(2b+1)) = (3(4b^2- 4b+1)+ 24b-2(4b^2+ 4b+1))/(6(2b-1)(2b+1)) = (12b^2- 12b+3+24b-8b^2- 8b-2)/(6(2b-1)(2b+1)) = (4b^2+ 4b+1)/(6(4b^2- 1)) = ((2b+1)^2)/(6(2b-1)(2b+1)) = (2b+1)/(12b-6).
8) (2b-1)/(4b+2) + 4b/(4b^2- 1) + (2b+1)/(3-6b) = (2b- 1^(\3(2b-1)))/(2(2b+1)) + (4b^(\6))/((2b-1)(2b+1)) – (2b+ 1^(\2(2b+1)))/(3(2b-1)) = (3(2b-1)^2+ 24b-2(2b+1)^2)/(6(2b-1)(2b+1)) = (3(4b^2- 4b+1)+ 24b-2(4b^2+ 4b+1))/(6(2b-1)(2b+1)) = (12b^2- 12b+3+24b-8b^2- 8b-2)/(6(2b-1)(2b+1)) = (4b^2+ 4b+1)/(6(4b^2- 1)) = ((2b+1)^2)/(6(2b-1)(2b+1)) = (2b+1)/(12b-6).