Назад
ГДЗ Алгебра 7 клас Мерзляк (2024)
§ 1. Алгебраїчні вирази
Реклама:
Подайте у вигляді добутку многочленів вираз:
1) (у + 1)2 – 4y(y + 1) = (y + 1)(y + 1– 4y) = (y + 1)(1– 3y);
2) 10(a2 – 5) + (a2 – 5)2 = (a2 – 5)(10 + a2 – 5) = (a2 – 5 )(a2 + 5);
3) (a – 2)2 – 6(a – 2) = (a – 2)(a – 2 – 6) = (a – 2)(a – 8).
4) (x – 6)(2x – 4) + (x – 6)(8 – x) = (x – 6)(2x – 4 + 8 – x) = (x – 6)(x + 4);
5) (x2 – 2)(3у + 5) – (x2 – 2)(y + 12) = (x2 – 2)(3у + 5 – (у + 12)) = = (x2 – 2)(2y – 7);
6) (4a – 3b)(5a + 8b) + (3b – 4a)(2a + b) = (4a – 3b)(5a + 8b) – (4a – 3b)(2a + b) = (4a – 3b)(5a + 8b – (2a + b)) = (4a – 3b)(3a + 7b);
7) (p – 9)4(2p + 1)3 + (p – 9)3(2p + 1)4 = (p – 9)3(2p + 1)3(p – 9 + 2p + 1) = (p – 9)3(2p + 1)3 ∙ (3p – 8).
1) (у + 1)2 – 4y(y + 1) = (y + 1)(y + 1– 4y) = (y + 1)(1– 3y);
2) 10(a2 – 5) + (a2 – 5)2 = (a2 – 5)(10 + a2 – 5) = (a2 – 5 )(a2 + 5);
3) (a – 2)2 – 6(a – 2) = (a – 2)(a – 2 – 6) = (a – 2)(a – 8).
4) (x – 6)(2x – 4) + (x – 6)(8 – x) = (x – 6)(2x – 4 + 8 – x) = (x – 6)(x + 4);
5) (x2 – 2)(3у + 5) – (x2 – 2)(y + 12) = (x2 – 2)(3у + 5 – (у + 12)) = = (x2 – 2)(2y – 7);
6) (4a – 3b)(5a + 8b) + (3b – 4a)(2a + b) = (4a – 3b)(5a + 8b) – (4a – 3b)(2a + b) = (4a – 3b)(5a + 8b – (2a + b)) = (4a – 3b)(3a + 7b);
7) (p – 9)4(2p + 1)3 + (p – 9)3(2p + 1)4 = (p – 9)3(2p + 1)3(p – 9 + 2p + 1) = (p – 9)3(2p + 1)3 ∙ (3p – 8).