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ГДЗ Алгебра 7 клас Істер (2024)
Реклама:
Запишіть вираз у вигляді добутку:
1) x9 – y6 = (x3)3 – (у2)3 = (x3 – y2)(x6 + x3y2 + y4);
2) –p12 – 27 = –((p4)3 + 33) = –(p4 + 3)(p8 – 3p4 + 9);
3) –a9b6 + 1 = 1 – (a3b2)3 = (1 – a3b2)(1 + a3b2 + a6b4);
4) 216p15 + 0,008t18 = (6p5)3 + (0,2t6)3 = (6p5 + 0,2t6)(36p10 – 1,2p5t6 + 0,04t12);
5) 64m21c3 – p30 = (4m7c)3 – (p10)3 = (4m7c – p10)(16m14c2 + 4m7ср10 + p20);
6) 512t24p27 – 729a33 = (8t8p9)3 – (9a11)3 = (8t8p9 –9a11) (64t16p18 + 72t8p9a11 + 81a22).
1) x9 – y6 = (x3)3 – (у2)3 = (x3 – y2)(x6 + x3y2 + y4);
2) –p12 – 27 = –((p4)3 + 33) = –(p4 + 3)(p8 – 3p4 + 9);
3) –a9b6 + 1 = 1 – (a3b2)3 = (1 – a3b2)(1 + a3b2 + a6b4);
4) 216p15 + 0,008t18 = (6p5)3 + (0,2t6)3 = (6p5 + 0,2t6)(36p10 – 1,2p5t6 + 0,04t12);
5) 64m21c3 – p30 = (4m7c)3 – (p10)3 = (4m7c – p10)(16m14c2 + 4m7ср10 + p20);
6) 512t24p27 – 729a33 = (8t8p9)3 – (9a11)3 = (8t8p9 –9a11) (64t16p18 + 72t8p9a11 + 81a22).