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ГДЗ Алгебра 7 клас Істер (2024)
Реклама:
Розкладіть на множники:
1) (р + 2)2 – 9 = (р + 2)2 – 32 = (р + 2 – 3)(р + 2 + 3) = (р – 1)(р + 5);
2) 16 – (m – 3)2 = 42 – (m – 3)2 = (4 – (m – 3))(4 + m – 3) = (7 –m)(1 + m);
3) (3х – 2)2 – 36 = (3х – 2)2 – 62 = (3х – 2 – 6)(3х – 2 + 6) = (3х – 8)(3х + 4);
4) x2 – (2x – 1)2 = (х – (2х – 1))(х + 2х – 1) = (1 – х)(3х – 1);
5) (5а – 3b)2 – 9b2 = (5а – 3b)2 – (3b)2 = (5а – 3b – 3b)(5а – 3b + 3b) = (5а – 6b) ∙ 5а;
6) (3х + 4у)2 – 100y3 = (3х + 4у)2 – (10y)2 = (3х + 4у – 10у)(3х + 4у + 10у) = (3х – 6у)(3х +14у) = 3(х – 2у)(3х + 14у).
1) (р + 2)2 – 9 = (р + 2)2 – 32 = (р + 2 – 3)(р + 2 + 3) = (р – 1)(р + 5);
2) 16 – (m – 3)2 = 42 – (m – 3)2 = (4 – (m – 3))(4 + m – 3) = (7 –m)(1 + m);
3) (3х – 2)2 – 36 = (3х – 2)2 – 62 = (3х – 2 – 6)(3х – 2 + 6) = (3х – 8)(3х + 4);
4) x2 – (2x – 1)2 = (х – (2х – 1))(х + 2х – 1) = (1 – х)(3х – 1);
5) (5а – 3b)2 – 9b2 = (5а – 3b)2 – (3b)2 = (5а – 3b – 3b)(5а – 3b + 3b) = (5а – 6b) ∙ 5а;
6) (3х + 4у)2 – 100y3 = (3х + 4у)2 – (10y)2 = (3х + 4у – 10у)(3х + 4у + 10у) = (3х – 6у)(3х +14у) = 3(х – 2у)(3х + 14у).