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ГДЗ Алгебра 7 клас Істер (2024)
Реклама:
Подайте вираз у вигляді добутку:
1) (x + 2)2 –1 = (x + 2 –1)(х + 2 + 1) = (х + 1)(х + 3);
2) 4 – (у + 3)2 = (22 – (у + 3)2 – (2 – (у + –3))(2 + у + 3) = (–1 –у) ∙ (5 + у);
3) (4m – 5)2 –16 = (4m – 5)2 – 42 = (4m – 5 – 4)(4m – 5 + 4) = (4m – 9)(4m – 1);
4) 6,25 – (а – 3,5)2 = 2,52 – (а – 3,5)2 = (2,5 – (а – 3,5))(2,5 + (а – 3,5)) = (2,5 – а + 3,5)(2,5 + а – 3,5) = (6 – а)(–1 + а);
5) (2х – 5)2 – 49 = (2x – 5)2 – 72 = (2x – 5 – 7)(2х – 5 + 7) = (2х – 12)(2х + 2) = 4(х – 6)(х + 1);
6) 1 – (2х + 1)2 = (1 – (2х + 1))(1 + 2х + 1) = –2х(2 + 2х) = –4х(1+х).
1) (x + 2)2 –1 = (x + 2 –1)(х + 2 + 1) = (х + 1)(х + 3);
2) 4 – (у + 3)2 = (22 – (у + 3)2 – (2 – (у + –3))(2 + у + 3) = (–1 –у) ∙ (5 + у);
3) (4m – 5)2 –16 = (4m – 5)2 – 42 = (4m – 5 – 4)(4m – 5 + 4) = (4m – 9)(4m – 1);
4) 6,25 – (а – 3,5)2 = 2,52 – (а – 3,5)2 = (2,5 – (а – 3,5))(2,5 + (а – 3,5)) = (2,5 – а + 3,5)(2,5 + а – 3,5) = (6 – а)(–1 + а);
5) (2х – 5)2 – 49 = (2x – 5)2 – 72 = (2x – 5 – 7)(2х – 5 + 7) = (2х – 12)(2х + 2) = 4(х – 6)(х + 1);
6) 1 – (2х + 1)2 = (1 – (2х + 1))(1 + 2х + 1) = –2х(2 + 2х) = –4х(1+х).