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ГДЗ Алгебра 7 клас Тарасенкова (2024)
Роздiл 3. Одночлени i многочлени
Реклама:
Розкладіть на множники вираз:
1) (5 + b)2 – b2 = (5 + b – b)(5 + b + b) = 5(5 + 2b);
2) (4 – b)2 – 16 = (4 – b)2 – 42 = (4 – b – 4)(4 – b + 4) = –b(8 – b);
3) у2 – (7 + у)2 = (y + 7 + y)(y – 7 – y) = –7(2y + 7);
4) x2 – (х + 1)2 = (x + x + 1)(x – x – 1) = –1(2x + 1);
5) (1 + х)2 – (1 – х)2 = (1 + x + 1 – x)(1 + x – 1 + x) = 4x;
6) (х + 2)2 – (2 + х)2 = (x + 2 + 2 + x)(x + 2 – 2 – x) = (2x + 4) • 0 = 0;
7) (х + 6)2 – (6 – х)2 = (x + 6 + 6 – x)(x + 6 – 6 + x) = 24x;
8) (Зx + 2)2 – (5 – х)2 = (3x + 2 + 5 – x)(3x + 2 – 5 + x) = (2x + 7)(4x – 3).
1) (5 + b)2 – b2 = (5 + b – b)(5 + b + b) = 5(5 + 2b);
2) (4 – b)2 – 16 = (4 – b)2 – 42 = (4 – b – 4)(4 – b + 4) = –b(8 – b);
3) у2 – (7 + у)2 = (y + 7 + y)(y – 7 – y) = –7(2y + 7);
4) x2 – (х + 1)2 = (x + x + 1)(x – x – 1) = –1(2x + 1);
5) (1 + х)2 – (1 – х)2 = (1 + x + 1 – x)(1 + x – 1 + x) = 4x;
6) (х + 2)2 – (2 + х)2 = (x + 2 + 2 + x)(x + 2 – 2 – x) = (2x + 4) • 0 = 0;
7) (х + 6)2 – (6 – х)2 = (x + 6 + 6 – x)(x + 6 – 6 + x) = 24x;
8) (Зx + 2)2 – (5 – х)2 = (3x + 2 + 5 – x)(3x + 2 – 5 + x) = (2x + 7)(4x – 3).