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ГДЗ Алгебра 7 клас Тарасенкова (2024)
Роздiл 3. Одночлени i многочлени
Спростіть вираз:
1) (–3ab + 2а2b) + (6аb – а2b + 5b) = –3ab + 2a2b + 6аb – a2b + + 5b = a2b + 3ab + 5b;
2) (2a2 + 3a + 4b) + (2a – 3a2 – b) = 2a2 + 3a + 4b + 2a – 3a2 – b = = –a2 + 5a + 3b;
3) (0,5a + b) + (1/2a + 2/3b) = 0,5a + b + 1/2a + 2/3b = a + 12/3b;
4) (12/3a2 + 6,3b2) + (–2/3a2 – 4b2) + (–a2 + 4) = 12/3a2 + 6,3b2 – 2/3a2 – 4b2 – a2 + 4 = 2,3b2 + 4;
5) (7xy2 + 7x2y – 5x2 + 2) + (Зxу + 3xy2 – x2) = 7xy2 + 7x2y – 5x2 + 2 + 3xy + 3xy2 – x2 = 7x2y + 10xy2 – 6x2 + 3xy + 2;
6) (а2 + 2b2) + (За2 + с – b2) + (–с – 2а2) + (–2а2 – b2) = а2 + 2b2 + За2 + с – b2 – с – 2а2 – 2а2 – b2 = 4а2 – 4а2 + 2b2 – 2b2 + c – c = 0;
7) 4,8а2 – 0,1аb + 5,6b2 + 3,7а2 – 3,5b2 – 2 – 3,1bа + 2 = 8,5а2 + 2,1b2 – 3,2аb.
1) (–3ab + 2а2b) + (6аb – а2b + 5b) = –3ab + 2a2b + 6аb – a2b + + 5b = a2b + 3ab + 5b;
2) (2a2 + 3a + 4b) + (2a – 3a2 – b) = 2a2 + 3a + 4b + 2a – 3a2 – b = = –a2 + 5a + 3b;
3) (0,5a + b) + (1/2a + 2/3b) = 0,5a + b + 1/2a + 2/3b = a + 12/3b;
4) (12/3a2 + 6,3b2) + (–2/3a2 – 4b2) + (–a2 + 4) = 12/3a2 + 6,3b2 – 2/3a2 – 4b2 – a2 + 4 = 2,3b2 + 4;
5) (7xy2 + 7x2y – 5x2 + 2) + (Зxу + 3xy2 – x2) = 7xy2 + 7x2y – 5x2 + 2 + 3xy + 3xy2 – x2 = 7x2y + 10xy2 – 6x2 + 3xy + 2;
6) (а2 + 2b2) + (За2 + с – b2) + (–с – 2а2) + (–2а2 – b2) = а2 + 2b2 + За2 + с – b2 – с – 2а2 – 2а2 – b2 = 4а2 – 4а2 + 2b2 – 2b2 + c – c = 0;
7) 4,8а2 – 0,1аb + 5,6b2 + 3,7а2 – 3,5b2 – 2 – 3,1bа + 2 = 8,5а2 + 2,1b2 – 3,2аb.