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ГДЗ Алгебра 7 клас Істер (2024)
2. ЦІЛІ ВИРАЗИ
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1) (2х – 3)(2х + 3) = (2х)2 – 32 = 4х2 – 9;
2) (3р + 8)(3р – 8) = (3р)2 – 82 = 9р2 – 64;
3) (4 + 5а)(5a – 4) = (5a + 4 )(5а – 4) = (5a)2 – 42 = 25а2 – 16;
4) (3m – 4р)(4р + 3m) = (3m – 4р)(3m + 4р) = (3m)2 – (4р)2 = 9m2 – 16m2;
5) (7а + 10b)(10b – 7а) = (10b + 7a)(10b – 7a) = 100b2 – 49a2;
6) (1/4p – 1/7q)( 1/7q + 1/4p) = (1/4p – 1/7q)( 1/4p + 1/7q) = (1/4p)2 – (1/7q)2 = 1/16p2 – 1/49q2.
1) (2х – 3)(2х + 3) = (2х)2 – 32 = 4х2 – 9;
2) (3р + 8)(3р – 8) = (3р)2 – 82 = 9р2 – 64;
3) (4 + 5а)(5a – 4) = (5a + 4 )(5а – 4) = (5a)2 – 42 = 25а2 – 16;
4) (3m – 4р)(4р + 3m) = (3m – 4р)(3m + 4р) = (3m)2 – (4р)2 = 9m2 – 16m2;
5) (7а + 10b)(10b – 7а) = (10b + 7a)(10b – 7a) = 100b2 – 49a2;
6) (1/4p – 1/7q)( 1/7q + 1/4p) = (1/4p – 1/7q)( 1/4p + 1/7q) = (1/4p)2 – (1/7q)2 = 1/16p2 – 1/49q2.