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ГДЗ Математика 7 клас Істер (2024)
Тема 5. МНОГОЧЛЕН
Реклама:
Перетворіть на многочлен стандартного вигляду:
1) (5ab2 – 12ab – 7a2b) – (15ab + 8a2b)= 5ab2 – 12ab – 7a2b – 15ab – 8a2b = 5ab2 – 27ab – 15a2b;
2) (3/5a3b2 – 3/4ab2) – (–5/8b2a – 7/10b2a3) = 3/5a3b2 – 3/4ab2 + 5/8ab2 + 7/10a3b2 = 3^(\2)/5a3b2 + 7/10a3b2 – 3^(\2)/4ab2 + 5/8ab2 = 13/10a3b2 – 1/8ab2;
3) (x + y – z =) – (–2х + 3y – z =) – (–5y + 4z + x)= x + y – z + 2x – 3y + z + 5y – 4z – x = 2x + 3у – 4z;
4) (2m – 3n) – (4m – 3mn + 3m2) – (5mn – 5n2 – 3n) = 2m – 3n – 4m + 3nn – 3m2 – 5mn + 5n2 + 3n = – 3m2 + 5n2 – 2m – 2mn.
1) (5ab2 – 12ab – 7a2b) – (15ab + 8a2b)= 5ab2 – 12ab – 7a2b – 15ab – 8a2b = 5ab2 – 27ab – 15a2b;
2) (3/5a3b2 – 3/4ab2) – (–5/8b2a – 7/10b2a3) = 3/5a3b2 – 3/4ab2 + 5/8ab2 + 7/10a3b2 = 3^(\2)/5a3b2 + 7/10a3b2 – 3^(\2)/4ab2 + 5/8ab2 = 13/10a3b2 – 1/8ab2;
3) (x + y – z =) – (–2х + 3y – z =) – (–5y + 4z + x)= x + y – z + 2x – 3y + z + 5y – 4z – x = 2x + 3у – 4z;
4) (2m – 3n) – (4m – 3mn + 3m2) – (5mn – 5n2 – 3n) = 2m – 3n – 4m + 3nn – 3m2 – 5mn + 5n2 + 3n = – 3m2 + 5n2 – 2m – 2mn.